(3x-5)(x+9)=0

Miguel Reynolds

Miguel Reynolds

Answered question

2021-12-18

(3x5)(x+9)=0

Answer & Explanation

otoplilp1

otoplilp1

Beginner2021-12-19Added 41 answers

To solve algebraically, set the separate monomial as zero and find the value of x.
(3x5)(x+9)=0
3x5=0
Add 5 on both sides,
3x5+5=0+5
3x=5
Divide both sides by 3,
3x3=53
x=53
Set next monomial as zero and find the value of x,
(3x5)(x+9)=0
x+9=0
subtract 9 on both sides,
x+99=09
x=9
After solving algebraically, we get x=53 and x=9.
Archie Jones

Archie Jones

Beginner2021-12-20Added 34 answers

(3x5)(x+9)=0
3x(x+9)5(x+9)=0
3x2+27x5x45=0
3x2+22x45=0
x=22±326
x=22+326
x=22326
x=53
x=9

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