What is the answer to this quadratic: 0=−2a2±2b−12 −2a2+2b−12=0

Question

What is the answer to this quadratic:  0=−2a2±2b−12  −2a2+2b−12=0

censoratojk · Accepted Answer

Step 1  2a2+2b−12=0 is not a solvable quadratic. I will assume you meant  2x2+2x−12  The quadratic formula is:  −b±b2−(4ac)2a  −2±22−(4×2−12)2×2  −2±4−(−96)4  −2±1004  −2±104  124 or 84  The answer is x=3 or x=2

Navreaiw · Accepted Answer

Step 1  Given equation: 2a2+2b−12=0  Quadratic equations like this one, with an x2 term but no x term, can still be solved using the quadratic formula, −b±b2−4ac2a, once they are put in standard form: ax2+bx+c=0  This equation is in standard form: ax2+bx+c=0  Substitute 2 for a, 0 fro b, and −12+2b for c in the quadratic formula, −b±b2−4ac2a  a=0±02−4×2(2b−12)2×2  Square 0  a=0±−4×2(2b−12)2×2  Multiply -4 times 2  a=0±−8(2b−12)2×2  Multiply -8 times −12+2b  a=0±96−16b2×2  Take the square root of 96−16b  a=0±46−b2×2  Multiply 2 times 2  a=0±46−b4  Now solve the equation a=0±46−b4 when ± is plus and minus  a=6−b  a=−6−b

RizerMix · Accepted Answer

Step 1 2a2+2b−12=0 Subtract 2a2 from both sides. Anything subtracted from zero gives its negation. 2b−12=−2a2 Add 12 to both sides 2b=−2a2+12 The equation is in standard form. 2b=12−2a2 Divide both sides by 2 2b2=12−2a22 Dividing by 2 undoes the multiplication by 2. b=12−2a22 Divide −2a2+12 by 2 b=6−a2

What is the answer to this quadratic: 0=-2a^{2}+-2b-12 -2a^{2}+2b-12=0

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