b2sonicxh

2021-12-31

How many liters of a 25% alcohol solution and how many liters of a 12% alcohol solution must be mixed to create 13 liters of a 15% alcohol solution?

Timothy Wolff

Beginner2022-01-01Added 26 answers

Step 1

Let the number of liters of 25% alcohol solution and 12% alcohol solution required be x and y

According to question,

$x+y=13$ (1)

$0.25x+0.12y=0.15\cdot 13$

$\Rightarrow 25x+12y=195$ (2)

Step 2

Multiply Eq.(1) with 12

$\Rightarrow 12x+12y=156$ (3)

Subtract Eq.(3) from (2)

$13x=39$

$\Rightarrow x=3$

From Eq.(1)

$x+y=13$

$\Rightarrow 3+y=13$

$\Rightarrow y=10$

To create 13 liters of a 15% alcohol solution we need 3 liters of 25% alcohol solution and 10 liters of 12% alcohol solution

Let the number of liters of 25% alcohol solution and 12% alcohol solution required be x and y

According to question,

Step 2

Multiply Eq.(1) with 12

Subtract Eq.(3) from (2)

From Eq.(1)

To create 13 liters of a 15% alcohol solution we need 3 liters of 25% alcohol solution and 10 liters of 12% alcohol solution

Lakisha Archer

Beginner2022-01-02Added 39 answers

10 liters 12.00% Alcohol 2

karton

Expert2022-01-04Added 613 answers

Solution A

Concentration = 25%=0.25

Amount =x

Solution B

Concentration = 12%=0.12

Amount = 13-x

Resultant Solution

Concentration = 15%=0.15

Amount = 13 liters

0.25x+0.12(13-x)=0.15 * 13

0.25x+1.56-0.12x=1.95

0.25x+1.56-0.12x=1.95

0.13x=1.95-1.56

0.13x=0.39

0.13x/13=0.39/13

x=3

Amount of solution A = x = 3 liters

Amount of solution B = 13-x = 13-3 = 10 liters

Answer

3 liters of a 25% alcohol solution must be mixed with 10 liters of 12% solution to get 13 liters of 15% solution.

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