Jason Yuhas
2021-12-28
Actinium-226 has a half-life of 29 hours. If 100 mg of actinium-226 disintegrates over a period of 58 hours, how many mg of actinium-226 will remain? Use .
Matthew Rodriguez
Beginner2021-12-29Added 32 answers
Step 1
The given data is:
Half life
Initial 100 mg
To find how many actinium-226 will remain after 58 hours.
Step 2
The given equation is:
(1)
At
Substitute the value of C in equation (1),
(2)
Step 3
At half life
Substitute the value of k in equation (2),
Step 4
Now find actinium-226 remain after 58 hours is,
Thus, the actinium remains after 58 hours is 25mg.
Jillian Edgerton
Beginner2021-12-30Added 34 answers
no of half lives (n)
Amount left
karton
Expert2022-01-04Added 613 answers
Solution:
Using formula:
A is final amount after time "t".
h is the half-life
Given:
h=29 hours
t=58 hours
A=?
A=25mg
25mg of actinium-226 will remain after 58 hours
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