Actinium-226 has a half-life of 29 hours. If 100 mg of actinium-226 disintegrates over a period of 58 hours, how many mg of actinium-226 will remain? Use .
The given data is:
Initial 100 mg
To find how many actinium-226 will remain after 58 hours.
The given equation is:
Substitute the value of C in equation (1),
At half life
Substitute the value of k in equation (2),
Now find actinium-226 remain after 58 hours is,
Thus, the actinium remains after 58 hours is 25mg.
no of half lives (n)
A is final amount after time "t".
h is the half-life
25mg of actinium-226 will remain after 58 hours
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