hadejada7x

2021-12-28

Suppose the rule of the function f is "add one" and the rule of the function g is "multiply by 4."

How can we express these functions algebraically?

$f\left(x\right)=$

$g\left(x\right)=$

$(f\circ g)\left(x\right)=$

$(f\circ g)\left(x\right)=$

How can we express these functions algebraically?

Ella Williams

Beginner2021-12-29Added 28 answers

Given:

Suppose the rule of the function f is "add one" and the rule of the function g is "multiply by 4".

Calculation:

To express the function algebraically:

Here, f and g are function of x.

From the given information,

$f\left(x\right)=x+1$

$g\left(x\right)=4x$

$(f\circ g)\left(x\right)=f\left(g\left(x\right)\right)$

$=f\left(4x\right)$

$(f\circ g)\left(x\right)=4x+1$ , (using $f\left(x\right)=x+1$ )

$(g\circ f)\left(x\right)=g\left(f\left(x\right)\right)$

$=g(x+1)$

$=4(x+1)$ , (using $g\left(x\right)=4x)$

$(g\circ f)\left(x\right)=4x+4$

Suppose the rule of the function f is "add one" and the rule of the function g is "multiply by 4".

Calculation:

To express the function algebraically:

Here, f and g are function of x.

From the given information,

Cassandra Ramirez

Beginner2021-12-30Added 30 answers

We have to find the algebraically function f and g where f is "add one" and g is "multiply by 4"

Solution:$f(\in put)=\in put+1$

$\Rightarrow f\left(x\right)=x+1$

and$g\left(x\right)=4x$

$(f\circ g)\left(x\right)=f\left(g\left(x\right)\right)=f\left(4x\right)=4x+1$

$(f\circ g)\left(x\right)=g\left(f\left(x\right)\right)=g(x+1)=4(x+1)$

$(f\circ g)\left(x\right)=4x+4$

Solution:

and

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