Donald Johnson

2021-12-27

Evaluate $e-\frac{1}{2}f\text{}when\text{}e=15\text{}{\textstyle \phantom{\rule{1em}{0ex}}}\text{and}{\textstyle \phantom{\rule{1em}{0ex}}}\text{}f=2$ .

Archie Jones

Beginner2021-12-28Added 34 answers

Given:

$e-\frac{1}{2}f$ (1)

$e=15,f=2$

substitute the values of e and f in equation (1)

we have

$15-\frac{1}{2}\left(2\right)$

$15-1$

14

Therefore$e-\frac{1}{2}f=14$

substitute the values of e and f in equation (1)

we have

14

Therefore

accimaroyalde

Beginner2021-12-29Added 29 answers

You enter the number for each letter into the equation when evaluating an expression.

$15-\frac{1}{2}\left(2\right)$ Now use order of operations to simplify

$15-1=14$

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