 deiteresfp

2021-12-26

It takes a person 50 minutes to get to campus. He spends t minutes walking to the bus stop and the rest of the time riding the bus. His walking rate is 0.06 miles per minute and the bus travels at a rate of 0.5 miles per minute. The total distance walking and traveling by bus is given by the algebraic expression $0.06t+0.5\left(50-1\right)$.
(a) Simplify the algebraic expression (b) Use each form of the algebraic expression to determine the total distance that the person travels if the person spends 20 minutes walking to the bus stop.
(a) The simplified expression is. (Do not factor.) (b) Using the given expression, it is found that the total distance that the person travels is miles if he spends 20 minutes walking to the bus stop. Using the simplified expression, it is found that the total distance that the person travels is miles if the person spends 20 minutes walking to the bus stop. John Koga

$\text{Walking time}=t$
$\text{Riding time}=50-t$

Part a) Simplifying the Algebraic Expression.
$0.06t+0.5\left(50-t\right)$
$=0.06t+25-0.5t$
$=25-0.44t$
Part b) if the Person spends 20 minutes walking to the bus stop.
Total distance travelled by him.
$=25-0.44t$
$=25-0.44×20$
$=25-8.8$
$=16.2$ miles otoplilp1

a) $d\left(t\right)=25-0.44t$
b) $d\left(t\right)=16.2$ mles
Step-by-step explanation:
Question incomplete.
From google, I found two question
a) Simplify algebraic expression
b) Use each form of the algebraic expression to determine the total distance that you travel if you spend 20 minutes walking to the bus stop
a) $d\left(t\right)=0,06t+0.5\left(50-t\right)$
$d\left(t\right)=0,06t+25-0,5t$
$d\left(t\right)=25-0.44t$
b) $d\left(t\right)=25-0.44t$
for
$d\left(t\right)=25-0.44\cdot \left(20\right)$
$d\left(t\right)=25-8.8$
$d\left(t\right)=16.2$ miles user_27qwe