Multiply the algebraic expressions using the FOIL method, and simplify. (2t+3)(t-1)

petrusrexcs

petrusrexcs

Answered question

2021-12-27

Multiply the algebraic expressions using the FOIL method, and simplify.
(2t+3)(t1)

Answer & Explanation

Samantha Brown

Samantha Brown

Beginner2021-12-28Added 35 answers

Step 1
The given expression is (2t+3)(t1)
FOIL method:
(a+b)(c+d)=ac+ad+bc+bd
Step 2
(2t+3)(t1)=2tt+2t(1)+3t+3(1)
=2t22t+3t3
=2t2+t3
Mary Goodson

Mary Goodson

Beginner2021-12-29Added 37 answers

Consider the algebraic expression
(2t+3)(t1)
Using the FOIL method,
(a+b)(c+d)=ac+ad+bc+bd
Then (2t+3)(t1)=2t(t1)+3(t1)
=2tt+2t(1)+3t+3(1)
=2t22t+3t+(3)
=2t2+t3
Therefore, (2t+3)(t1)=2t2+t3
Vasquez

Vasquez

Expert2022-01-08Added 669 answers

(2t+3)(t1)
(a+b)(c+d)=ac+ad+bc+bd
(2t+3)(t1)=2t(t1)+3(t1) Distributive property
=2tt+2t(1)+3t+3(1) Distributive property
=2t22t+3t+(3) Laws of exponents and multiply
=2t2+t3 Combine like terms and simplify
Answer: (2t+3)(t1)=2t2+t3

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?