garnentas3m

2021-12-29

Find the value of x so that the slope of the line through the points $(x,-3)\text{}{\textstyle \phantom{\rule{1em}{0ex}}}\text{and}{\textstyle \phantom{\rule{1em}{0ex}}}\text{}(4,5)\text{}is\text{}\frac{2}{3}$

alexandrebaud43

Beginner2021-12-30Added 36 answers

Step 1

Given information:

The slope of line is 2/3.

The given points are (x,-3) and (4,5).

Step 2

Calculation:

The slope of the line passing through two point is calculated by$m=\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}$

Step 3

The points are (x,-3) and (4,5).

$\frac{2}{3}=\frac{5-(-3)}{4-x}$

$2(4-x)=3(5+3)$

$8-2x=24$

$2x=8-24$

$2x=-16$

$x=-8$

Step 4

Final statement: The value of x is -8.

Given information:

The slope of line is 2/3.

The given points are (x,-3) and (4,5).

Step 2

Calculation:

The slope of the line passing through two point is calculated by

Step 3

The points are (x,-3) and (4,5).

Step 4

Final statement: The value of x is -8.

eskalopit

Beginner2021-12-31Added 31 answers

Step 1

We know that the slope of line that passes through$(x1,x2)\text{}{\textstyle \phantom{\rule{1em}{0ex}}}\text{and}{\textstyle \phantom{\rule{1em}{0ex}}}\text{}(y1,y2)\text{}is\text{}m=\frac{y2-y1}{x2-x1}$ .

By using it we can calculate the value of x.

$m=\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}$

$m=\frac{5-(-3)}{4-x}$

$\frac{2}{3}=\frac{8}{4-x}$

$8-2x=24$

$2x=8-24=-16$

$x=-8$

Step 2

Answer:$x=-8$ .

We know that the slope of line that passes through

By using it we can calculate the value of x.

Step 2

Answer:

Vasquez

Expert2022-01-08Added 669 answers

We know that the slope of line that passes through

8-2x=24

2x=8-24=-16

x=-8

Answer: x=-8

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