Painevg

2021-12-27

To solve:
$10x-2\left(x+4\right)=8\left(x-2\right)+6$

Mary Herrera

Step 1
Given: $10x-2\left(x+4\right)=8\left(x-2\right)+6$
By distributive property,
$-2\left(x+4\right)=-2×x+\left(-2\right)×4$
$-2\left(x+4\right)=-2x-8$
By distributive property,
$8\left(x-2\right)=8×x-8×2$
$8\left(x-2\right)=8x-16$
Replace $-2\left(x+4\right)$ with $-2x-8$
Replace $8\left(x-2\right)$ with $8x-16$
$10x-2\left(x+4\right)=10-2x-8$
$10x-2\left(x+4\right)=8x-8$
$8\left(x-2\right)+6=8x-16+6$
$8\left(x-2\right)+6=8x-10$
$8x-8=8x-10$
Add $-8x+8$ on both sides,
$8x-8-8x+8=8x-10-8x+8$
$0x+0=-2+0x$
$0x=-2$
As there is no x term, no solution exists for the equation.

braodagxj

Step 1
$10x-2\left(x+4\right)=8\left(x-2\right)+6$
Expand $-2\left(x+4\right):\phantom{\rule{1em}{0ex}}-2x-8$
$10x-2x-8=8\left(x-2\right)+6$
Add similiar elements: $10x-2x=8x$
$8x-8=8\left(x-2\right)+6$
Expand $8\left(x-2\right)+6:\phantom{\rule{1em}{0ex}}8x-10$
$8x-8=8x-10$
$8x-8+8=8x-10+8$
Simplify
$8x=8x-2$
Subtract 8x from both sides
$8x-8x=8x-2-8x$
Simplify
$0=-2$
The sides are not equal
No solution

karton