Which method do you use to solve 7x2+8x+100?

Question

Which method do you  use to solve  7x2+8x+100?

Brynn Ortiz · Accepted Answer

Step 1
A quadratic equation is simply another way of solving a problem if the solution cannot be factored logically.
First we can start with some quick review:
Let’s say we have the equation

x^{2} + 2 x - 3

for example. This equation could be solved logically using the factors of the first and last terms.
To begin, we can state the factors of the first term,

x^{2}

. Imagine there’s an invisible 1 in front of the

x^{2}

, therefore the factors are 1, because only

1 \times 1

, or

- 1 \times - 1

will multiply to get one. Then we can analyze the third term, -3. The factors of -3 are either

1 \times - 3

, or

- 1 \times 3

Now we can check and see if any of the factors can combine in order to get

a + 2

the middle term (don’t worry about the x’s, those will carry over). Recall

1 = - 1, 1

and

- 3 = 1, - 1, 3, - 3

From our factors we can use a -1 and a 3 to get +2. Therefore,

(x + 3) (x - 1) = 0

is our derived factorization. Then plug in the values to make the statement true, -3 or 1 will both result in an answer of 0 and our the possible values for x.
However, when the logical factorization seen above is not possible, we can plug our numbers into the quadratic equation.

a x^{2} + b x + c

is the standard way we view an equation. Using the values from the equation above,

a = 1, b = 2,

and

c = - 3

After our a, b, and c values are found we can plug them into the actual quadratic equation.

\frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}

Note : This equation may look intimidating, but as long as you follow factoring rules, you should have no problem. It’s totally normal to come out with an answer containing square roots.

immablondevl · Accepted Answer

Step 1 We do not &#039;&#039;solve&#039;&#039; expressions. Perhaps you want to know how to solve the equation 7x2+8x+100=0 Or perhaps you want to know how to factor the expression 7x2+8x+100 In order to do the second for this expression, we&#039;ll have to do the first. That&#039;s because this expression is irreducible using real, rational coefficients. Solve: 7x2+8x+100=0 Spend a little time factoring, but not too much, because we know we can always solve by the quadratic formula. x=−b±b2−ac2a For the equation we&#039;re working on: x=−(8)±(8)2−4(7)(100)2(7) so x=−8±64−280014=−8±−273614 =−8±1219i14=−47±6197i Note Simplifying 2736 is not trivial. 2736 is divisible by 9 (the digits add up to 18, which is divisible by 9) 2736=9×304 304 is divisible by 4 (half or 304 is still even, so we can divide again) 2736=9×4×76 (half of 76 is 38, still even) 2736=9×4×4×19 So 2736=9×4×4×19=3×2×2×19=1219 Now that we know the zeros of 7x2+8x+100 are z1 and z2, we can factor the quadratic as (x−z1)(x−z2), so: 7x2+8x+100=(x−(−47+6197i))(x−(−47−6197i))

Which method do you use to solve 7x^{2}+8x+100?

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