How do you solve x(x-4)-2=43?

David Rojas

David Rojas

Answered question

2022-01-23

How do you solve
x(x4)2=43?

Answer & Explanation

porekalahr

porekalahr

Beginner2022-01-24Added 10 answers

Step 1
x(x4)2=43
x×xx×42=43
x24x243=4343
x24x45=0
Δ=(4)24×1×(45)
Δ=196
x=b±Δ2a
x1=(4)1962
x2=(4)+1962
x1=5, x2=9
0 here's our answer!
Mazzuranavf

Mazzuranavf

Beginner2022-01-25Added 10 answers

Step 1
Expand the bracket
x(x4)2=43x24x2=43
Subtract 43 from both sides
x24x45=0
Factorise
(x9)(x+5)=0
So x=9 or -5

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