Explained: "How do you solve 4x2−16=0?"

logosomatw

Answered question

2022-01-21

How do you solve

4 x^{2} - 16 = 0

Kaitlynn Noble

Beginner2022-01-22Added 12 answers

Step 1

4 x^{2} - 16

fits the difference of squares property

a^{2} - b^{2}

, which can be factored as

(a + b) (a - b)

Here, we can take the square root of

4 x^{2}

which is 2x and we can take the square root of 16 which is

\pm 4

Thus,

a = 2 x

and

b = \pm 4

, so we have

(2 x + 4) (2 x - 4) = 0

We can factor a 2 out of both expressions to get

2 (x + 2) (x - 2)

Setting the factors equal to zero, we get

x = \pm 2

lilwhitelieyc

Beginner2022-01-23Added 10 answers

Step 1
1) Add 16 to both side to get

4 x^{2} = 16

2) Divide both sides by 4 to get

x^{2} = 4

3) Find the square root of both sides to get

x = \pm 2

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