Question: "To determine: −10x2+30x−20=0?"

High School
Algebra
Algebra I
Quadratic function and equation

ndimiimpercea2

Answered question

2022-01-21

To determine:

- 10 x^{2} + 30 x - 20 = 0

Answer & Explanation

Kudusind

Beginner2022-01-22Added 11 answers

Step 1
Given: $- 10 x^{2} + 30 x - 20 = 0$
Multiplying both sides with -1
We get,
$10 x^{2} - 30 x + 20 = 0$
By Using quadratic formula
$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$
we get,
$\Rightarrow x = \frac{30 \pm \sqrt{30^{2} - 4 \times 10 \times 20}}{2 \times 10}$
$\Rightarrow x = \frac{30 \pm 10}{20}$
$\Rightarrow x = \frac{40}{20}, x = \frac{20}{20}$
Thus we get the value of x as $x = 2, 1$

Addisyn Thompson

Beginner2022-01-23Added 16 answers

Step 1
Given:

- 10 x^{2} + 30 x - 20 = 0

- 10 (x^{2} - 3 x + 2) = 0

Dividing both sides by 10 we get

x^{2} - 3 x + 2 = 0

x^{2} - x - 2 x + 2 = 0

x (x - 1) - 2 (x - 1) = 0

(x - 2) (x - 1) = 0

x - 2 = 0

x = 2

NKS

x - 1 = 0

x = 1

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