Rewrite expression without absolute value bars. abs(7- pi)

Joni Kenny

Joni Kenny

Answered question

2020-10-18

Rewrite expression without absolute value bars.
|7π|

Answer & Explanation

Theodore Schwartz

Theodore Schwartz

Skilled2020-10-19Added 99 answers

Step 1
The given expression is |7π|.
Absolute value:
The algebraic definition of absolute value is as follows:
|a|={aifa0aifa<0
Step 2
Now,
7π>0
|7π|=7π or approximately 3.858
The absolute value of a positive number is the number within the absolute value bars.

2021-09-07

7-3.1415926
Mr Solver

Mr Solver

Skilled2023-05-28Added 147 answers

Result:
7π if 7π0
or
(7π) if 7π<0
Solution:
To rewrite the expression |7π| without absolute value bars, we need to consider two cases: when the expression inside the absolute value bars is positive and when it is negative.
Case 1: When 7π is non-negative (greater than or equal to zero):
In this case, |7π| simplifies to the expression itself, so we can write it as:
7π
Case 2: When 7π is negative:
In this case, the expression inside the absolute value bars becomes its negation. Therefore, we can write it as:
(7π)
Combining both cases, we can rewrite the expression |7π| without absolute value bars as:
7π if 7π0
or
(7π) if 7π<0
Nick Camelot

Nick Camelot

Skilled2023-05-28Added 164 answers

Case 1: When 7π is positive:
In this case, we can rewrite |7π| as simply (7π).
|7π|=(7π)=7π
Case 2: When 7π is negative:
In this case, the expression |7π| becomes (7π), as the absolute value of a negative number is the positive value of that number.
|7π|=(7π)=7+π
Hence, the expression |7π| can be rewritten as the sum of two cases:
|7π|={7π,if 7π07+π,if 7π<0
Now, substituting the value of π with its approximate value (π3.14159), we can calculate the final result:
|7π|={73.14159,if 73.1415907+3.14159,if 73.14159<0
Calculating the two cases:
Case 1: When 73.141590:
73.14159=3.85841
Case 2: When 73.14159<0:
7+3.14159=3.85841
Therefore, the final result is 3.858.
madeleinejames20

madeleinejames20

Skilled2023-05-28Added 165 answers

To rewrite the expression without absolute value bars, |7π|, we need to consider the cases when the expression inside the absolute value is positive and when it is negative.
Case 1: When 7π is positive, the expression simplifies to 7π:
|7π|=7π
Case 2: When 7π is negative, the expression simplifies to (7π):
|7π|=(7π)
Combining both cases, we can write the expression without absolute value bars as follows:
|7π|={7π,if 7π0(7π),if 7π<0

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