Find the limit of the sequence d_n=\frac{3^n2^{n+3}}{4^{-n}n!}

Kaydence Huff

Kaydence Huff

Answered question

2022-01-22

Find the limit of the sequence
dn=3n2n+34nn!

Answer & Explanation

Hana Larsen

Hana Larsen

Beginner2022-01-23Added 17 answers

We have
dn=3n2n+34nn!
Simplify
dn=23×(3×2×4)nn!
dn=8×(24)nn!
Some of terms of series
8×11+8×2411+8×24221+8×24331+
ex=1+x11+x221+x331+
x=24
Given series limit 8×e24

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