Find the first four terms of each of the recursively

2alr8w

2alr8w

Answered question

2022-01-23

Find the first four terms of each of the recursively defined sequences
dk=k(dk1)2 for all integers k1
d0=3

Answer & Explanation

ma90t66690

ma90t66690

Beginner2022-01-24Added 7 answers

The recursive definition of the given sequence is dk=k(dk1)2 for all integers k1
The first term of the sequence is d0=3
Evaluate the second term d1 using dk=k(dk1)2 and d0=3
d1=(1)(d11)2
=(d0)2
=32
=9
Now, evaluate the third term d2 using dk=k(dk1)2 and d1=9
d2=(2)(d21)2
=2(d1)2
=2(9)2
=162
Now, evaluate the fourth term d3 using dk=k(dk1)2 and d2=162
d3=(3)(d31)2
=3(d2)2
=3(162)2
=78732
Thus, the first four terms are: 3,9,162,78732

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