Give the first six terms of the following sequences. 1)g1=2 and g2=1 2)c1=4,c2=5 and cn=cn−1×cn−2 for n≥3 3)b1=1,b2=3 and bn=bn−1−bn−2 for n≥3 4)d1=1,d2=1 and dn=(dn−1)2+dn−2 for n≥3

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Give the first six terms of the following sequences.    1)g1=2 and g2=1     2)c1=4,c2=5 and cn=cn−1×cn−2 for n≥3    3)b1=1,b2=3 and bn=bn−1−bn−2 for n≥3    4)d1=1,d2=1 and dn=(dn−1)2+dn−2 for n≥3

utgyrnr0 · Accepted Answer

Given    1)g1=2 and g2=1, gn=ngn−1+9n−2    g3=3g2+g1=3×1+2=5    g4=4g3+g2=4×5+1=21    g5=5g4+g3=5×21+5=110    g6=6g5+g4=6×110+21=660+21=681    so first six terms are: 2,1,5,21,110,681    2)c1=4,c2=5 and cn=cn−1×cn−2 for n≥3    c3=c2×c1=5×4=20    c4=c3×c2=20×5=100    c5=c4×c3=100×20=2000    c6=c5×c4=2000×100=200000    Thus, the first six terms are: 4,5,20,100,2000,200000

Eleanor Shaffer · Accepted Answer

3)b1=1,b2=3 and bn=bn−1−bn−2 for n≥3    b3=b2−7b1=3−7=−4    b4=b3−7b2=−4−21=−25    b5=b4−7b3=−25+28=3    b6=b5−7b4=3+175=178    4)d1=1,d2=1 and dn=(dn−1)2+d0n−2 for n≥3    d3=(d2)2+d1=12+1=2    d4=(d3)2+d2=22+1=5    d5=(d4)2+d3=52+2=27    d6=(d5)2+d4=272+5=734

Give the first six terms of the following sequences. 1)g_1=2 and

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