Consider the population of bacteria described earlier. This population grows

logosomatw

logosomatw

Answered question

2022-01-29

Look at the group of microorganisms that was mentioned earlier. According to the function f(t) = 200e02, where t is measured in minutes, this population expands. A. After five hours (or 300 minutes), how many germs are still in the population? B. When does the number of bacteria reach 100,000?

Answer & Explanation

Wilson Mitchell

Wilson Mitchell

Beginner2022-01-30Added 8 answers

f=200e0.02t
Putting=300 in (1) we get
f(300)=200(e(0.02×300))=200(e6)=80685.758780686
Putting f(t)=100000 in(1) we get
100000=200e0.02
e0.02=100000200
e0.02=500
Taking logarithm on both the sides we get
In(e0.02)=In500
Using propertiesof logarithms we get
0.02tIne=In500
0.02t×1=In500
0.02t=In500
t=In5000.02
t=310.73 minutes =311 minutes
(A)The number of bacteria present in the population after 5hours (300 minutes) = 80686
(B)Time taken by the population to reach 100000 bacteria =311 minutes

waijazar1

waijazar1

Beginner2022-01-31Added 13 answers

i`m so grateful for this

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