Ms. Ragounath drove over a nail and the

mk14

mk14

Answered question

2022-02-13

Ms. Ragounath drove over a nail and the tire of her car started to leak air. If the car lost .4% of its air daily, when will her tire have three-quarters of its original air pressure which was 38 psi?

Answer & Explanation

nick1337

nick1337

Expert2023-04-23Added 777 answers

Let's first calculate how much air pressure the tire will lose each day:

0.4% of 38ψ=(0.004)38ψ=0.152ψ

So, every day the tire will lose 0.152ψ of air pressure.

Now, let x be the number of days it takes for the tire to have three-quarters of its original air pressure.

To solve for x, we can set up the following equation:

38ψ-(0.152ψday)x=(34)38ψ

We can simplify this equation by multiplying both sides by 43:

(43)38ψ-(43)(0.152ψday)x=38ψ

Simplifying further:

(43)(38ψ-0.152ψdayx)=38ψ

Multiplying both sides by 34:

38ψ-0.152ψdayx=(34)38ψ

Now we can substitute the known values:

38ψ-0.152ψdayx=28.5ψ

Adding 0.152ψdayx to both sides:

38ψ-28.5ψ=0.152ψdayx

Simplifying:

9.5 psi = 0.152 psi/day * x

Dividing both sides by 0.152ψday:

x=62.5 days

Therefore, it will take approximately 62.5 days for Ms. Ragounath's tire to have three-quarters of its original air pressure of 38 psi, assuming the tire loses 0.4% of its air pressure every day.

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