Trent Carpenter

2021-01-25

Find the absolute max and min values at the indicated interval

$f\left(x\right)=2{x}^{3}-{x}^{2}-4x+10,[-1,0]$

Raheem Donnelly

Skilled2021-01-26Added 75 answers

Given,

Absolute maximum and absolute minimum values of a function exist at a point where its first derivative is zero or at the end points of the given interval.

So first we find the derivative of the given function:

Now

Now computing the value of the function at these points and at the end points of the interval:

at

at

at

We didn't find the value of f(1), because 1 does not belongs to the interval [-1,0].

Hence absolute maximum value is 12.8148 and absolute minimum value is 10.

Jeffrey Jordon

Expert2021-11-11Added 2605 answers

Answer is given below (on video)

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