How would you solve the following system of linear equations:2x1+(3+a)x2+2x3=2+ax1+ax2+2x3=aax1+2x2+2ax3=0assuming that a≠±2? I feel confident in solving linear equation systems with just constants as the coefficients but the variable coefficient a is what gives me problems.Here is the solution I find: solution as augmented matrix but how would the assumption about a make the reduced echelon form any different compared to an assumption about e.g.a≠±2?

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Balraj Conrad · Accepted Answer

With  x1=a−ax2−2x3  can we eliminate x1:  x2(3−a)−2x3=2−a  x2(2−a2)+4ax3=−a2  And then using  x3=x2(3−a)−(2−a)2  to eliminate x3. Then you will get  x2(2−a2)+2a(3−a)x2−2a(2−a)=−a2

How would you solve the following system of linear equations: 2x_1 + (3+a)x_2 + 2x_3 = 2+aZ

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