Why am I not able to find the

poplavileqlo

poplavileqlo

Answered question

2022-03-13

Why am I not able to find the intersection of circles (x2)2+(y5)2=5 and (x1)2+(y+3)2=50 algebraically?

Answer & Explanation

Talan Kent

Talan Kent

Beginner2022-03-14Added 4 answers

Step 1
You simplified the quadratic wrong:
(328y)24(328y)+4+y210y+25=5
1024512y+64y2128+32y+4+y210y+25=5
(64+1)y2+(512+3210)y+(1024128+4+255)=0
65y2490y+920=0
The y coefficient should be -490 not -494.
guinder0ir

guinder0ir

Beginner2022-03-15Added 3 answers

Step 1
From the correct equation
65y2490y+920=0
You get 2 solutions: y=4, 4613.
Subtituting in in one of the equation x=328y gives x=0,4813, respectively.
Note that the equation of line that you got x=328y, describes correctly the line on which both points lie.

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