Lorelei Stanton
2022-03-30
Prove: if has an integer root, has an integer root too, for com'
Melody Gamble
Beginner2022-03-31Added 10 answers
Step 1
In this answer, p and q are co' integers such that (and p can be zero or negative). We want to show that if has an integer solution, then so does
If is an integer root of , then
If , then . Because , this means . Then, the equation which is equivalent to , has an integer solution
From now on, suppose that . That is, for some integer s. Hence,
Therefore,
Therefore, s divides p and q, which implies as p and q are co'. Since , we get
Therefore, and . Hence,
That is, is an integer solution to the quation
The condition is necessary. Note that and satisfies the condition that has an integer solution, but does not have an integer solution.
Jared Kemp
Beginner2022-04-01Added 14 answers
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