Provide the solution 1)\(\displaystyle{\log{{3}}}{\left({x}^{{2}}+{2}\right)}={3}\) 2)\(\displaystyle{{\log}_{{3}}{\left({x}+{4}\right)}}={{\log}_{{3}}{\left({2}{x}-{4}\right)}}\) 3)\(\displaystyle{{\log}_{{2}}{\left({3}{x}+{5}\right)}}\geq{{\log}_{{2}}{\left({x}-{9}\right)}}\) 4)\(\displaystyle{{\log}_{{4}}{\left({x}+{1}\right)}}{

mwombenizhjb

mwombenizhjb

Answered question

2022-03-30

Provide the solution
1)log3(x2+2)=3
2)log3(x+4)=log3(2x4)
3)log2(3x+5)log2(x9)
4)log4(x+1)<log4(2x)

Answer & Explanation

Jared Kemp

Jared Kemp

Beginner2022-03-31Added 14 answers

Logarithm rules: blogbx=x
If ba=x, then logbx=a
1)log3(x2+2)=3
x2+2=33
x2+2=27
x2=272
x2=25
x=25
x=±5
2)log3(x+4)=log3(2x4)
3log3(x+4)=3log3(2x4)
x+4=2x4
x2x=44
x=8
x=8
Dixie Reed

Dixie Reed

Beginner2022-04-01Added 15 answers

(c)log2(3x+5)log2(x9)
2log2(3x+5)log2(x9)
3x+5x9
3x+55x95
3xx14
3xxx14x
2x14
x7
(d)log4(x+1)<log4(2x)
4log4(x+1)<2x
x+1<2x
x+12x<2x2x
x+1<0
x+11<01
x<1
x>1

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