\(\displaystyle{\left({\frac{{{r}}}{{\sqrt{{{r}^{{2}}-{1}}}}}},{\frac{{{r}}}{{\sqrt{{{r}^{{2}}+{1}}}}}}\right)}\) are roots of the equation

Erik Cantu

Erik Cantu

Answered question

2022-03-30

(rr21,rr2+1) are roots of the equation x2bx+3=0. What is the value of b?

Answer & Explanation

Ashley Olson

Ashley Olson

Beginner2022-03-31Added 12 answers

Step 1
Let α and β be the roots of the equation with β>α
1α2=1-1r2
1β2=1+1r2
1α2+1β2=2
α2+β2=18
α2+β2+2αβ=24
b2=24

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