How to solve \(\displaystyle\omega^{{4}}-{\left[{\left({\frac{{{e}{B}}}{{{m}}}}\right)}^{{2}}+{2}{\omega_{{0}}^{{2}}}\right]}\omega^{{2}}+{\omega_{{0}}^{{4}}}={0}\) in the simplest way

Blackettyl2j

Blackettyl2j

Answered question

2022-03-31

How to solve
ω4[(eBm)2+2ω02]ω2+ω04=0
in the simplest way

Answer & Explanation

Aidyn Wall

Aidyn Wall

Beginner2022-04-01Added 10 answers

Step 1
4ω2=2(eBm)2+4ω02± 2[(eBm)2+2ω02]24ω04
=2(eBm)2+4ω02± 2(eBm)4+4(eBm)2ω02
=2(eBm)2+4ω02± 2(eBm)(eBm)2+4ω02
=[eBm±(eBm)2+4ω02]2
so it gives you the "nice" formula for the roots of
ω2±eBωmω02

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