How to solve this bi-quadratic example? \(\displaystyle{5}{\left({\frac{{{x}+{1}}}{{{x}}}}\right)}^{{2}}-{16}{\left({\frac{{{x}-{1}}}{{{x}}}}\right)}-{52}={0}\)

Asher Olsen

Asher Olsen

Answered question

2022-04-01

How to solve this bi-quadratic example?
5(x+1x)216(x1x)52=0

Answer & Explanation

Marquis Ibarra

Marquis Ibarra

Beginner2022-04-02Added 9 answers

Step 1
5(x+1x)216(x1x)52=0
5(1+1x)216(11x)52=0
5+10x+5x216+16x52=0
Step 2
5x2+26x63=0
(5x9)(1x+7)=0
Or 5t2+26t63=0
where t=1x.
Cody Hart

Cody Hart

Beginner2022-04-03Added 11 answers

Let 1x=a
we get:
5a2+26a63=0
a=95, so x=59
a=9,x=19.

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