Prove that \(\displaystyle{\frac{{\pi^{{e}}}}{{{x}-{e}}}}+{\frac{{{e}^{\pi}}}{{{x}-\pi}}}+{\frac{{\pi^{\pi}+{e}^{{e}}}}{{{x}-\pi-{e}}}}={0}\) has one real root

Caerswso1pc

Caerswso1pc

Answered question

2022-04-02

Prove that πexe+eπxπ+ππ+eexπe=0 has one real root in (e,π) and other in (π,π+e).

Answer & Explanation

Ben Castillo

Ben Castillo

Beginner2022-04-03Added 13 answers

The roots of
f(x)=πexe+eπxπ+ππ+eexπe=0
and g(x)=πe(xπ)(xπe)+eπ(xe)(xeπ)+(ππ+ee)(xe)(xπ)=0
would coincide Note that
g(e)=π1+e(πe)>0,g(π)=eπ+1(πe)<0,g(e+π)=eπ(ππ+ee)>0
This proves that the quadratic g(x) has one real root in (e,π) and other one in (π,π+)e. So will be the case for f(x)=0.

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