Region of the coefficients of a quadratic equation

Aryan Salinas

Aryan Salinas

Answered question

2022-03-30

Region of the coefficients of a quadratic equation that cause the roots of it to be in the unit disk
From Simon Haykin's Adaptive Filter Theory: consider the characteristic equation is 1+a1z1+a2z2=0, then for the roots to be inside the unit circle (or in the unit disk), the coefficients of the quadratic must satisfy the following conditions: 1a1+a2,1a2a1, and 1a21.
I could figure this out some of the way. For complex roots it follows that the coefficients lie in the region defined by the intersection of 4a2>a12 and a2<1. For real roots, I could prove that |a2|<1, and obviously 4a2a12. But I cannot figure out how the line boundaries of the region can be derived.

Answer & Explanation

Jared Kemp

Jared Kemp

Beginner2022-03-31Added 14 answers

From the quadratic equation
z=da12±(da12)2a2
For the greater real root and the upper boundary on the real line
1a12+(a12)2a2  1+a12+(a12)2a2  1+a1+(a12)2(a12)2a2  a1+a21
For the lesser real root and the lower boundary on the real line
1a12(a12)2a2  1+a12(a12)2a2  1+a1+(a12)2(a12)2a2  1a2a1
For the complex roots being inside the unit circle
1|a12±ia2(a12)2|  1(a12)2+a2(a12)2  1a2  12(a2)2  1|a2|  1a21

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