Solving for y, given \(\displaystyle{x}={\frac{{-{1}+\sqrt{{{1}+{\left({4}\frac{{y}}{{50}}\right)}}}}}{{{2}}}}\)

aanvarendbq28

aanvarendbq28

Answered question

2022-03-31

Solving for y, given
x=1+1+(4y50)2

Answer & Explanation

armejantm925

armejantm925

Beginner2022-04-01Added 20 answers

This is the formula for the quadratic function
f=ax2+bx+c. In this case we have a=1 and b=1. Comparing 4ac=4c with 4y50 gives c=y50. Thus
f=x2+xy50=0
exinnaemekswr1k

exinnaemekswr1k

Beginner2022-04-02Added 10 answers

It's simple algebra.
y=50(2x+1)2504=50x(x+1)

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