Find the general solution of: \(\displaystyle{{\sin}^{{2}}{x}}{{\cos}^{{2}}{x}}+{\sin{{x}}}{\cos{{x}}}-{1}={0}\)

Blaze Shepherd

Blaze Shepherd

Answered question

2022-04-14

Find the general solution of:
sin2xcos2x+sinxcosx1=0

Answer & Explanation

Dubliddissefyf8

Dubliddissefyf8

Beginner2022-04-15Added 10 answers

Step 1
Now,
(sin2x+1)2=5,
which is impossible because
0(sin2x+1)24.

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