Solve for x(a) 82−x=2(b) (12)x&lt;18(c) 5x=25x−2(d) 3x+2≥27(e) 43x=8x−1

a) 82−x=2(23)2−x=226−3x=216−3x=16−1=3x53=xb) (12)x&lt;1812x&lt;12323&lt;2x3&lt;xx&gt;3c) 5x=25x−25x=(52)x−25x=52x−4x=2x−44=2x−xx=4

(d) 3x+2≥273x+2≥(3)3x+2≥3x≥3−2x≥1(e) 43x=8x−1(22)3x=(23)x−126x=23x−36x=3x−36x−3x=−33x=−3x=−1

a) 82−x=2(23)2−x=226−3x=216−3x=16−1=3x53=xb) (12)x&lt;1812x&lt;12323&lt;2x3&lt;xx&gt;3c) 5x=25x−25x=(52)x−25x=52x−4x=2x−44=2x−xx=4

(d) 3x+2≥273x+2≥(3)3x+2≥3x≥3−2x≥1(e) 43x=8x−1(22)3x=(23)x−126x=23x−36x=3x−36x−3x=−33x=−3x=−1

Answered: "Solve for x(a) 82−x=2(b) (12)x<18(c) 5x=25x−2(d) 3x+2≥27(e) 43x=8x−1"

Kale Mcclain

2022-04-21

Solve for x
(a)

8^{2 - x} = 2

(b)

{(\frac{1}{2})}^{x} < \frac{1}{8}

(c)

5^{x} = 25^{x - 2}

(d)

3^{x + 2} \geq 27

(e)

4^{3 x} = 8^{x - 1}

Payton Cantrell

Beginner2022-04-22Added 15 answers

8^{2 - x} = 2

{(2^{3})}^{2 - x} = 2

2^{6 - 3 x} = 2^{1}

6 - 3 x = 1

6 - 1 = 3 x

\frac{5}{3} = x

{(\frac{1}{2})}^{x} < \frac{1}{8}

\frac{1}{2^{x}} < \frac{1}{2^{3}}

2^{3} < 2^{x}

3 < x

x > 3

5^{x} = 25^{x - 2}

5^{x} = {(5^{2})}^{x - 2}

5^{x} = 5^{2 x - 4}

x = 2 x - 4

4 = 2 x - x

x = 4

attefrimibeocx

Beginner2022-04-23Added 14 answers

(d)

3^{x + 2} \geq 27

3^{x + 2} \geq {(3)}^{3}

x + 2 \geq 3

x \geq 3 - 2

x \geq 1

(e)

4^{3 x} = 8^{x - 1}

{(2^{2})}^{3 x} = {(2^{3})}^{x - 1}

2^{6 x} = 2^{3 x - 3}

6 x = 3 x - 3

6 x - 3 x = - 3

3 x = - 3

x = - 1

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