Solve please \frac{x^2-4}{x-2}=2 \frac{x+4}{x-2}=0 \frac{x-3}{x+2}\geq0 \frac{x+2}{x+3}<\frac{x-1}{x-2}

Naomi Hopkins

Naomi Hopkins

Answered question

2022-04-19

Solve please
x24x2=2
x+4x2=0
x3x+20
x+2x+3<x1x2

Answer & Explanation

tigging9k0

tigging9k0

Beginner2022-04-20Added 19 answers

1)x24x2=2
x24=2x4
x2=2x
x22x=0
x=0, x=2
2)x+4x2=0
x+4=0
x=4
Sarai Dorsey

Sarai Dorsey

Beginner2022-04-21Added 16 answers

(3)x3x+20
x30
x3
(4)x+2x+3<x1x2
(x+2)(x2)<(x1)(x+3)
x24<x2+2x3
2x34
2x1
x12

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