Adelyn Rodriguez

2022-04-04

Solve for the variables b and c in the system of equations:

$\{\begin{array}{l}6b+2c=-2\\ 6b+4c=3\end{array}$

Juliet Mcdonald

Beginner2022-04-05Added 15 answers

Write the problem as a mathematical expression.

$6b+2c=-2$

$6b+4c=3$

Solve for $b$ in $6b+2c=-2$.

$b=-\frac{1}{3}-\frac{c}{3}$

$6b+4c=3$

Replace all occurrences of $b$ with $-\frac{1}{3}-\frac{c}{3}$ in each equation.

$-2+2c=3$

$b=-\frac{1}{3}-\frac{c}{3}$

Solve for $c$ in $-2+2c=3$.

$c=\frac{5}{2}$

$b=-\frac{1}{3}-\frac{c}{3}$

Replace all occurrences of $c$ with $\frac{5}{2}$ in each equation.

$b=-\frac{7}{6}$

$c=\frac{5}{2}$

List all of the solutions.

$b=-\frac{7}{6},c=\frac{5}{2}$

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