Solving a system of quadratic inequalities <mstyle scriptlevel="0"> <mo maxsize="2.047em"

Iyana Macdonald

Iyana Macdonald

Answered question

2022-05-12

Solving a system of quadratic inequalities
c 2 ( x 2 + y 2 ) + 2 c ( x + y ) + 2 + 1 2 = c
For a given positive integer c, I am trying to define algebraically, in terms of x & y, the region in 2D space for which the above equation and the following conditions hold:
1. c N
2. 0 x , y 1
I.E, which constraints/inequalities x & y must fulfill (in terms of c)

Answer & Explanation

Aibling6n2re

Aibling6n2re

Beginner2022-05-13Added 16 answers

As it is pointed out in OP, the inequalities (1),(2) can be written in one as
c c 2 ( x 2 + y 2 ) + 2 c ( x + y ) + 2 + 1 2 < c + 1
or
c 1 2 c 2 ( x 2 + y 2 ) + 2 c ( x + y ) + 2 < c + 1 2
Since c is a positive integer, the last double inequality is equivalent to
( c 1 2 ) 2 ( c x + 1 ) 2 + ( c y + 1 ) 2 < ( c + 1 2 ) 2 and further to

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