How to prove the existence of solution of a non linear system of equations Writing the ortogonality

poklanima5lqp3

poklanima5lqp3

Answered question

2022-05-14

How to prove the existence of solution of a non linear system of equations
Writing the ortogonality condition for any element of O ( n ), I've arrived to:
If we take n = 2, we know that Λ Λ T = I, so:
( x y z t ) ( x z y t ) = ( 1 0 0 1 )
This yields:
{ x 2 + y 2 = 1 x z + y t = 0 z 2 + t 2 = 1
Visually, these equations mean that we can find two orthonormal vectors.
We could generalise our reasoning to arbitrary dimension easily.
How could I prove rigorously, without plugging in any numbers nor functions, that this system of equations has solution (infinite, in fact)?
Is there any method to prove the existence of solution of non non linear equations (or systems)?

Answer & Explanation

Mollie Roberts

Mollie Roberts

Beginner2022-05-15Added 21 answers

The first and third equations states that points ( x , y ) and ( z , t ) are on a unit circle. Let's write that as:
x = cos ϕ
y = sin ϕ
z = cos ψ
t = sin ψ
Now we may write the second equation as:
cos ϕ cos ψ + sin ϕ sin ψ = 0
This may be rewritten as:
cos ( ϕ ψ ) = 0
Which has a solution:
ϕ ψ = π 2 + k π
We should restrict the angles to ( π , π ):
ϕ = ψ ± π 2
Which means that for each ( x , y ) on a unit circle there are two possible ( z , t ).
Jaeden Weaver

Jaeden Weaver

Beginner2022-05-16Added 4 answers

Your system for arbitrary dimension n is equivalent to finding an orthonormal basis in R n (put its elements as solumns in your matrix), which, in its turn is trivial.

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