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Elisha Kelly

Elisha Kelly

Answered question

2022-05-22

Solve the system of equations:
2 x 5 2 x 3 y x y 2 + 10 x 3 + y 2 5 y = 0 ( x + 1 ) y + 5 = y 3 x 2 + x 2

Answer & Explanation

Bettoldi1l

Bettoldi1l

Beginner2022-05-23Added 7 answers

Solving your second equation for y we get:
y 1 = 3 x 2 + ( x / 2 + 1 / 2 + 1 / 2 13 x 2 2 x + 29 ) x x / 2 + 5 / 2 + 1 / 2 13 x 2 2 x + 29
or
y 2 = 3 x 2 + ( x / 2 + 1 / 2 1 / 2 13 x 2 2 x + 29 ) x x / 2 + 5 / 2 1 / 2 13 x 2 2 x + 29
plugging this into the first equation we get the following polynomial (after squaring again)
157 x 10 466 x 9 + 281 x 8 663 x 7 + 345 x 6 405 x 5 242 x 4 + 121 x 3 190 x 2 + x + 1 = 0
which can only be solved by a numerical way.

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