solve the following linear system x 1 </msub> &#x2212;<!-- − --> 3 x 2

Theresa Archer

Theresa Archer

Answered question

2022-06-15

solve the following linear system
x 1 3 x 2 + x 3 = 1
2 x 1 x 2 2 x 3 = 2
x 1 + 2 x 2 3 x 3 = 1
by using gauss-jordan elimination method. The augmented matrix of the linear system is
( 1 3 1 1 2 1 2 2 1 2 3 1 ) .
By a series of elementary row operations, we have
( 1 3 1 1 0 5 4 0 0 0 0 2 ) .
My question is, although the question asked us to solve the linear system using gauss-jordan elimination method, can we stop immediately and conclude that the linear system is inconsistent without further apply any elementary row operation to the matrix
( 1 3 1 1 0 5 4 0 0 0 0 2 )
until the matrix
( 1 3 1 1 0 5 4 0 0 0 0 2 )
is transformed into reduced-row echelon form?

Answer & Explanation

Misael Li

Misael Li

Beginner2022-06-16Added 14 answers

Yes, you can stop there and conclude that the system is inconsistent as 0 2. If you were to continue to reduce the matrix to reduced-row echelon form, row 3's inconsistency would remain unaffected.
( 1 0 7 5 0 0 1 4 5 0 0 0 0 1 )
R 3 1 2 R 3 was performed to get the new row 3 and notice that the completely reduced-row echelon form above also has 0 x 1 + 0 x 2 + 0 x 3 = 1 0 = 1 which is not possible, and hence the system still maintains its inconsistency.
Semaj Christian

Semaj Christian

Beginner2022-06-17Added 12 answers

You can conclude that the system is inconsistent, because the last row of your matrix implies that 0 x 1 + 0 x 2 + 0 x 3 = 2, which cannot be satisfied.

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