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Emmy Dillon

Emmy Dillon

Answered question

2022-06-14

Given linear system:
4 + δ 1 δ 2 0 2 δ 1 + δ 2 0 1 + δ 1 δ 2 + δ 3 0
How from there it follows that δ 2 = δ 3 = 0 and δ 1 0?

Answer & Explanation

Jayce Bates

Jayce Bates

Beginner2022-06-15Added 18 answers

Defining δ 12 = δ 1 δ 2
4 + δ 12 0 δ 12 4 2 δ 12 0 δ 12 2 1 + δ 12 + δ 3 0 δ 3 δ 12 1
So the solution domain in the δ 12 x δ 3 .
Now, focusing on the δ 1 x δ 2 :
δ 12 4 δ 2 δ 1 + 4 δ 12 2 δ 2 δ 1 2
kixEffinsoj

kixEffinsoj

Beginner2022-06-16Added 3 answers

It doesn't, try
δ 1 = δ 2 = δ 3 = 1.

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