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Peyton Velez

Peyton Velez

Answered question

2022-06-13

Let f : R R be a continuous function and g : R R be a Lipschitz function. Would you help me to prove that the system of differential equation
x = g ( x )
y = f ( x ) y
with initial value x ( t 0 ) = x 0 and y ( t 0 ) = y 0 has a unique solution.
Could I prove the uniqueness solution of x = g ( x ), x ( t 0 ) = x 0 by Gronwall Inequality first then use the result to prove the second?

Answer & Explanation

alisonhleel3

alisonhleel3

Beginner2022-06-14Added 23 answers

Your reasonning is correct. Since g is Lipschitz and the first equation of the system involves only x, there is a unique solution x ( t ) such that x ( t 0 ) = x 0 .
The second equation becomes
y = f ( x ( t ) ) y , y ( t 0 ) = y 0 .
It is a linear equation and has a unique solution, given by
y ( t ) = y 0 e t 0 t f ( x ( s ) ) d s .
Gabriella Sellers

Gabriella Sellers

Beginner2022-06-15Added 4 answers

My answer is suppose ( x 1 ( t ) , y 1 ( t ) ) and ( x 2 ( t ) , y 2 ( t ) ) is solution. First, write x 1 ( t ) = x 0 + t 0 t x ( s ) d s the do the same for x 2 ( t ) and get | x 1 x 2 | = | t 0 t g ( x 1 ) g ( x 2 ) d s | K t 0 t | x 1 x 2 | d s. I doubt about this separation process.

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