let 0 < x <

Ezekiel Yoder

Ezekiel Yoder

Answered question

2022-06-26

let 0 < x < y and x , y be irrational number .Does it exist ?

Answer & Explanation

Cristian Hamilton

Cristian Hamilton

Beginner2022-06-27Added 23 answers

x y = y x ,
by dividing both sides by x x you'll arrive at
x y x x = x y x = x x ( y / x 1 ) = y x x x = ( y x ) x .
Under your assumption x > 0, raising both sides to power 1 / x gives
x y / x 1 = y x .
You assume y > x, so you have
(1) y x = 1 + 1 u
with some u > 0, and you obtain
x 1 / u = 1 + 1 u .
Raising both sides to power u implies
(2) x = ( 1 + 1 u ) u .
Combining ( 1 ) and ( 2 ) you get
(3) y = ( 1 + 1 u ) u + 1 .
So you see that ( 2 ) and ( 3 ) with some real u > 0 give all real solutions 0 < x < y of your equation, indeed.

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