For what a does this system of inequalities have only one solution? { <mtable column

dikcijom2k

dikcijom2k

Answered question

2022-06-29

For what a does this system of inequalities have only one solution?
{ y x 2 + 4 a 2 x y 2 + 4 a 2
So, I have tried getting y from the first equation then putting it into second, but then I have two quadratic and x, which of these quadratics are the first term? I know that I have to put it into Δ = 0. But don't really get which of them are first, second etc. Even tried subtracting second to first.

Answer & Explanation

Jaelynn Cuevas

Jaelynn Cuevas

Beginner2022-06-30Added 16 answers

If ( x 0 , y 0 ) , x 0 y 0 is a solution then ( y 0 , x 0 ) is also a solution. So in order to have only one solution, one must have x = y. Plugging y = x in the first equation one gets:
x 2 x + 4 a 2 0
Which has an unique solution iff Δ = 1 ( 4 a ) 2 = 0 which is equivalent to a = ± 1 4
invioor

invioor

Beginner2022-07-01Added 3 answers

If ( x , y ) is a solution so is ( y , x ), so for one solution we need x = y – we thus seek a for which y = x 2 + 4 a 2 is tangent to y = x, i.e. x 2 x + 4 a 2 has one solution, hence zero discriminant. Here Δ = 1 16 a 2 = 0, so a = ± 1 4 where the only solution is ( x , y ) = ( 1 / 2 , 1 / 2 ).

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?