Show that arbitrarly close to any rational number there is a real (non-rational) number. In other wo

veneciasp

veneciasp

Answered question

2022-07-02

Show that arbitrarly close to any rational number there is a real (non-rational) number. In other words, show that to each real ε > 0 and each rational r Q there exists x R Q with | x r | < ε

Answer & Explanation

soosenhc

soosenhc

Beginner2022-07-03Added 16 answers

For every n N you have
2 Q 1 n 2 Q
Now let ε > 0, then n can be found such that
1 n 2 < ε
Now for arbitrary r Q and given ε > 0 chose x = r + 1 n 2 Q
| x r | = | r + 1 n 2 r | = 1 n 2 < ε

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?