How would you solve the following system of equations: x 2 + y = 4 x + y 2 = 10I tried defining y in terms of x and then inserting in to the second equation: y = 4 − x 2 x + ( 4 − x 2 ) 2 = 10Expand the second equation: x + 16 − 8 x 2 + x 4 = 10Rearrange the terms: x 4 − 8 x 2 + x + 6 = 0

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How would you solve the following system of equations:      x    2    +  y  =  4    x  +      y    2    =  10I tried defining y in terms of x and then inserting in to the second equation:  y  =  4  −      x    2      x  +  (  4  −      x    2        )    2    =  10Expand the second equation:  x  +  16  −  8      x    2    +      x    4    =  10Rearrange the terms:      x    4    −  8      x    2    +  x  +  6  =  0

Savion Stanton · Accepted Answer

y  =  4  −      x    2  put it in 2nd equation  x  +  (  4  −      x    2        )    2    =  10  x  +  16  +      x    4    −  8      x    2    =  10      x    4    −  8      x    2    +  x  +  6  =  0      x    4    −      x    3    +      x    3    −  7      x    2    −      x    2    +  7  x  −  6  x  +  6  =  0      x    4    −      x    3    +      x    3    −      x    2    −  7      x    2    +  7  x  −  6  x  +  6  =  0      x    3    (  x  −  1  )  +      x    2    (  x  −  1  )  −  7  x  (  x  −  1  )  −  6  (  x  −  1  )  =  0  (  x  −  1  )  (      x    3    +      x    2    −  7  x  −  6  )  =  0    ⟹    x  −  1  =  0    ⟹    x  =  1solve the above equation one of the value of   x  =  1 and   y  =  3

Dayanara Terry · Accepted Answer

To solve general equations of the form   a      x    4    +  b      x    3    +  c      x    2    +  d  x  +  e  =  0 requires quartic formula.

How would you solve the following system of equations: x 2 </msup> + y =

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