Lorena Lester

2022-07-16

Solve,

$6{x}^{2}+x-2=0$

$6{x}^{2}+x-2=0$

coolng90qo

Beginner2022-07-17Added 14 answers

Step 1

factor the following $6{x}^{2}+x-2=0$

Step 2

Factor the quadratic $6{x}^{2}+x-2=0$

The coefficient of ${x}^{2}$ is 6 and the constant term is −2.

The product of 6 and −2 is −12. The factors of −12 which sum to 1 are −3 and 4.

So $6{x}^{2}+x-2=6{x}^{2}+4x-3x-2=2(2x-1)+3x(2x-1):$

$2(2x-1)+3x(2x-1):$

Factor $2x-1$ from $2(2x-1)+3x(2x-1)=(2x-1)(3x+2)$

Now set $(2x-1)(3x+2)=0$

$(2x-1)=0$ and $(3x+2)=0$

$x=\frac{1}{2}$ and $x=\frac{-2}{3}$

factor the following $6{x}^{2}+x-2=0$

Step 2

Factor the quadratic $6{x}^{2}+x-2=0$

The coefficient of ${x}^{2}$ is 6 and the constant term is −2.

The product of 6 and −2 is −12. The factors of −12 which sum to 1 are −3 and 4.

So $6{x}^{2}+x-2=6{x}^{2}+4x-3x-2=2(2x-1)+3x(2x-1):$

$2(2x-1)+3x(2x-1):$

Factor $2x-1$ from $2(2x-1)+3x(2x-1)=(2x-1)(3x+2)$

Now set $(2x-1)(3x+2)=0$

$(2x-1)=0$ and $(3x+2)=0$

$x=\frac{1}{2}$ and $x=\frac{-2}{3}$

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