Apply the first fundamental theorem of calculus to each function over the interval indicated. f(x)=(3x)/(x^2 +1) over [-1, 1]

Paxton Hoffman

Paxton Hoffman

Answered question

2022-07-26

Apply the first fundamental theorem of calculus to each function over the interval indicated.
f ( x ) = 3 x x 2 + 1 over [-1,1]

Answer & Explanation

Reinfarktq6

Reinfarktq6

Beginner2022-07-27Added 18 answers

f ( x ) = 3 x x 2 + 1 over [-1,1]
1 1 3 x x 2 + 1 d x = 3 1 1 x x 2 + 1 d x = 3 2 2 2 1 u d u = 0
remember a a f ( x ) d x = 0
x 2 + 1 = u
x = 1 u = 2
2xdx=du
x = 1 u = 2
xdx=du/2

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