The directions say to: Find b^2 -4ac and the number of real solutions to each equation. The equation is: -2x^2 +5x-6=0

atarentspe

atarentspe

Answered question

2022-09-02

The directions say to: Find b 2 4 a c and the number of real solutions to each equation. The equation is:
2 x 2 + 5 x 6 = 0

Answer & Explanation

Anabelle Hicks

Anabelle Hicks

Beginner2022-09-03Added 13 answers

Given 2 x 2 + 5 x 6 = 0
Implies that a = -2 , b=5 and c = -6
Hence b 2 4 a c = 5 2 4 ( 2 ) ( 6 ) = 25 48 = 23
Since b 2 4 a c is less than zero , there are no (ZERO REAL SOLUTION) real solutions to the given quadratic equation.
Makayla Reilly

Makayla Reilly

Beginner2022-09-04Added 3 answers

they want you to use the quadratic formula but only find the inside square root part
x = b ± b 2 4 a c 2 a ,
in the form of
a x 2 + b x + c = 0
so... 5 2 4 ( 2 ) ( 6 )
we get -23

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