We have a jar of coins, all quarters and dimes. All together,they are worth $17.60, We have 13 more than quarters than dimes.How many quarters, how many dimes?

IJzerboor07

IJzerboor07

Answered question

2022-09-05

We have a jar of coins, all quarters and dimes. All together,they are worth $17.60, We have 13 more than quarters than dimes.How many quarters, how many dimes?

Answer & Explanation

buciumau5r

buciumau5r

Beginner2022-09-06Added 8 answers

Turn the word problem into a function. Weknow that the sum of the quarters and dimes equal $17.60 and thatthere are 13 more quarters than dimes.
$17.60 = number of quarters + number of dimes
number of quarters = number of dimes + 13
Therefore you can set up the function of : 17.60 = 0.25(x+13)+0.10x note: x is the number of dimes.
17.60 = 0.25(x+13) + 0.10x
17.60 = 0.25x + 3.25 + 0.10x
14.35 = 0.25x +0.10x
14.35 = 0.35x
x = 41
Since x is the number of dimes,we now know that there are 41 dimes and 54 quarters.
iescabroussexg

iescabroussexg

Beginner2022-09-07Added 4 answers

The first thing you got to do is find out how many dimes makea dollar and how many quarters make up a dollar.
One dollar is equivalent to 10 dimes or 4 quarters. So 1dime is equivalent to $0.10, and one quarter is equivalent to$0.25.
Lets take the number of dimes to be x. Since thereare 13 more quarters than dimes, you get the number of dimes asx + 13.
You can form an eqaution using this information. The sum of thenumber of dollars in x dimes and x+13 quarters should be $17.60.
0.10x + 0.25(x + 13) = 17.60
Solve this eqaution for x. This value of x will give you the number of dimes. Add 13 to this value to find the number of quarters.

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