Solving simultaneous equations with `min{}` functionx1=min{a+b*x2, c};x2=min{a+b*x3, c};...xm=min{a+b*x1, c};

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coccusk7 · Accepted Answer

Let&#039;s consider simpler similar system of equationsLet b &amp;lt;&amp;gt; 0 (otherwise, if b == 0, x1 = x2 = a)x1 = a + b*x2x2 = a + b*x1from here you can find thatx1 = x2 = a/(1-b), b &amp;lt;&amp;gt; 0And this solution will be effective for the system of equations:x1 = a + b*x2x2 = a + b*x3...xn = a + b*x1and x1 = x2 = x3 = ... = xn = a/(1-b)Now we can apply the results to your system of equations, and solution is:x1 = x2 =x3 = ... xn == a/(1-b), if b &amp;lt;&amp;gt; 0 and a/(1-b) &amp;lt; c= c, if b &amp;lt;&amp;gt; 0 and a/(1-b) &amp;gt;= c= a, if b == 0 and a &amp;lt; c= c, if b == 0 and a &amp;gt;= c

Solving simultaneous equations with `min{}` function x1=min{a+bx2, c};x2=min{a+bx3, c};..xm=min{a+b*x1, c};

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